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<div class="moz-cite-prefix">Careful... HPO<img alt="$_4^{2-}$"
style="vertical-align: middle;"
src="cid:part1.92571970.0CFFB55B@mercer.edu"> is the polyatomic
ion hydrogen phosphate. In the case of KH<img alt="$_2$"
style="vertical-align: middle;"
src="cid:part2.608DCF1F.F3EABB32@mercer.edu">PO<img alt="$_4$"
style="vertical-align: middle;"
src="cid:part3.01751156.3F274D04@mercer.edu"> the hydrogen is
not part of the polyatomic ion so you have to specify it
explicitly.<br>
<br>
<br>
On 09/13/2017 04:57 PM, wrote:<br>
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<blockquote type="cite"
cite="mid:b2da2f2850034b48b9b74560a8f1aca3@spiderman.MercerU.local">
<pre wrap="">Dr. Pounds,
As I review problem # 2.61 in the book, I come across the problem “name the following compounds a) KH(2 this is on bottom)PO(4)
B) K(2)HPO(4) . Okay. So the first answer is Potassium Di Hydrogen Phosphate and the second answer is just Potassium Hydrogen Phosphate. If Hydrogen is part of the 7 dimolecular elements, why are we specifying it has 2 in A, and it has one in B without making it known? When we just say Potassium Hydrogen Phosphate, I know we have to get the cations to equal 3 to cancel the negative 3 out on the phosphate, but How do we know the Potassium is the one that gets the extra without specifying. Because Hydrogen is always supposed to have 2.
This is a mess. I really hope you can follow my question.
I hope you’re no longer in the dark, and I will see you tomorrow!
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<p><br>
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<pre class="moz-signature" cols="72">--
Andrew J. Pounds, Ph.D. (<a class="moz-txt-link-abbreviated" href="mailto:pounds_aj@mercer.edu">pounds_aj@mercer.edu</a>)
Professor of Chemistry and Computer Science
Mercer University, Macon, GA 31207 (478) 301-5627
<a class="moz-txt-link-freetext" href="http://faculty.mercer.edu/pounds_aj">http://faculty.mercer.edu/pounds_aj</a>
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