[CHM 112] Problem 80 and Additional Problems for Chapter 14

[Andrew J. Pounds]

So the rate is always going to be some type of concentration per
second.  I the cases I showed you it was in moles per liter seconds.  
In some of the problems you will M/sec or, in other words, Molarity per
second.  Since Molarity is moles per liter it is the rate expression is
the same thing as moles per liter seconds.

Does that help? 

On 02/07/2013 08:53 PM, wrote:
> Dr. Pounds,
>
> I know its late and you probably wont get a chance to get back to me before class tomorrow, but I just had a question about the suggested problems.
>
> You say unit of rate is always Mole/Liter*Sec, but #7 says the rate is M/S. I'm confused if the rate always has to be M/L*S, or if it can just be M/S like in problem 7, which doesn't seem to mention liters at all.
>
> Thanks and I'll be seeing you in class tomorrow.
>
> Regards,
>

-- 
Andrew J. Pounds, Ph.D.  (pounds at theochem.mercer.edu)
Associate Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627