[CHM 112] Question: Chp. 11 Additional Problem

[Andrew J. Pounds]

On 06/26/14 00:32, wrote:
> Hello Dr. Pounds,
>
> I'm stuck on one of the additional problems (Chapter 11, problem 4). In the first part of the solution
>   q=[(506 g)/(18.0 g/mol)] (6.01 kj/mol) is used. What is this equation and why is it used?
>
> Thank you,

This is an energy balance thing (look back at section 5.4 of your text), 
if there is not enough energy released to cool the water, then some of 
the ice will still be in solid form.

q is the "heat" required to melt the ice.  You have to determine this by 
computing $\Delta H$ for the reaction

H2O (s) -> H2O (l)

If you use the tables in the back of the book, you will get something 
close to the value I have on the solutions.  Now, this is per mole of 
ice, so I have to figure out how many moles of ice I have, that is where 
the ratio (506 g)/(18.0 g/mol) comes into play.


-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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