[CHM 112] Homework Question

[Andrew J. Pounds]

> ​Dr. Pounds,
>
>
> On question 15.23, I am using the equation: Kp=Kc(RT)^Δn
>
> Kc= 1.8x10^-5
>
> R=.08206
>
> T=623
>
> Δn=1
>
> so the overall equation is
>
> Kp=(1.8x10^-5)[(.08206)(623)]^1
>
> which equals to:
>
> 9.20x10^-4
>
> but the actual answer is: 3.5x10^-7
>
> what am I doing wrong?
>
You are correct on the following things...

$K_p = K_c (RT)^{\Delta n}$

$\Delta n$ = 1

but if you read the problem carefully they are giving you $K_p$ and 
asking you to come up with $K_c$, so the equation
is rearranged to

\documentclass{article} \usepackage[utf8x]{inputenc} \pagestyle{empty} 
\begin{document} $K_c = \frac{K_p}{(RT)^{\Delta n}}$ %this is where your 
LaTeX expression goes \end{document}

If you then substitute in the values for $K_p$, $R$, and $T$ that you 
used you should come up with the same value found in the book.

Make sense?

-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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