[CHM 112] Rate law question
Andrew J. Pounds
pounds_aj at mercer.edu
Tue Jun 30 20:20:49 EDT 2020
On 6/30/20 6:33 PM,
> How do I determine if a reaction is second or first order by looking
> at the rate law?
So for a reaction with ONE COMPONENT, the order is the exponent to which
the concentration is raised.
$rate=k [A]$
would be a first order reaction and
$rate=k[A]^2$
would be a second order reaction.
> Also could you explain finding the k constant through half life? I was
> too busy writing to catch everything.
>
> Get Outlook for iOS <https://aka.ms/o0ukef>
So when HALF of the compound is gone, the concentration is equal to
$[A]/2$, Referring to page 142 from the lecture slides, we are
considering a first order reaction and are using the FIRST ORDER
INTEGRATED RATE LAW, e.g ---
$[A] = [A_0] e^{-kt}$
so at the HALF LIFE (when half of the original compound is gone)
$\frac{[A_0]}{2} = [A_0] e^{-kt_{\frac{1}{2}}}$
this simplifies to
$\frac{1}{2} = e^{-kt_{\frac{1}{2}}}$
I take the natural log of both sides to arrive at
$\ln{\frac{1}{2}} = -kt_{\frac{1}{2}}$
$-0.6931=-kt_{\frac{1}{2}}$
or...
$\frac{0.6931}{k}=t_{\frac{1}{2}}$
or
$\frac{0.6931}{t_{\frac{1}{2}}}=k$
For first order reactions if you are given the half life you can easily
find $k$
--
Andrew J. Pounds, Ph.D. (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Director of the Computational Science Program
Mercer University, Macon, GA 31207 (478) 301-5627
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