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<div class="moz-cite-prefix">In the numerator you missed a cubed
term.<br>
<br>
0=104-((2.00+x)(1.00+3x))/((6.50-x)(8.50-x))<br>
<br>
should be<br>
<br>
0=104-((2.00+x)(1.00+3x)^3)/((6.50-x)(8.50-x))<br>
<br>
On 07/12/13 14:35, wrote:<br>
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<p>Hey Dr. Pounds,</p>
<p>I was doing the additional problems for chapter 15 and 18. I
was working on number 3 and I used my solver to find x. You
got the value 2. 44. I keep getting 5.94. Can you help me
figure out what I am doing wrong.
</p>
<p>This is what I put into my calculator for the equation.</p>
<p> </p>
<p>0=104-((2.00+x)(1.00+3x))/((6.50-x)(8.50-x))</p>
<p>My x was set to 0 and then my bounds were {0,6,50}</p>
<p>I clicked alpha enter. I still am not getting the correct
answer.</p>
<p> </p>
<p> </p>
<p>Thank you!</p>
<p> </p>
<p> </p>
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<br>
<br>
<pre class="moz-signature" cols="72">--
Andrew J. Pounds, Ph.D. (<a class="moz-txt-link-abbreviated" href="mailto:pounds_aj@mercer.edu">pounds_aj@mercer.edu</a>)
Professor of Chemistry and Computer Science
Mercer University, Macon, GA 31207 (478) 301-5627
<a class="moz-txt-link-freetext" href="http://faculty.mercer.edu/pounds_aj">http://faculty.mercer.edu/pounds_aj</a>
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