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Toward the end of Friday's lecture I showed you some useful
relationships for going between hydronium ion and hydroxide ion
concentrations and pH. I encourage you to know these and how to use
these in preparation for a quiz that you will have on Tuesday at the
end of class.<br>
<br>
<img style="vertical-align: middle"
src="cid:part1.06050504.01060107@mercer.edu"
title="\documentclass{article}
\usepackage[utf8x]{inputenc}
\pagestyle{empty}
\begin{document}
\begin{eqnarray*}
K_w &=& \mathrm{[H_3O^+][OH^-] = 1\times 10^{-14}}\\
\mathrm{pH} &=& \mathrm{-\log[H_3O^+]}\\
\mathrm{pOH} &=& \mathrm{-\log[OH^-]}\\
pK_w &=& 14\\
pK_w &=& \mathrm{pH} + \mathrm{pOH}\\
\mathrm{[H_3O^+]} &=& \mathrm{10^{-pH}}\\
\mathrm{[OH^-]} &=& \mathrm{10^{-pOH}}\\ \end{eqnarray*}
%this is where your LaTeX expression goes
\end{document}
" alt="\documentclass{article}
\usepackage[utf8x]{inputenc}
\pagestyle{empty}
\begin{document}
\begin{eqnarray*}
K_w &=& \mathrm{[H_3O^+][OH^-] = 1\times 10^{-14}}\\
\mathrm{pH} &=& \mathrm{-\log[H_3O^+]}\\
\mathrm{pOH} &=& \mathrm{-\log[OH^-]}\\
pK_w &=& 14\\
pK_w &=& \mathrm{pH} + \mathrm{pOH}\\
\mathrm{[H_3O^+]} &=& \mathrm{10^{-pH}}\\
\mathrm{[OH^-]} &=& \mathrm{10^{-pOH}}\\ \end{eqnarray*}
%this is where your LaTeX expression goes
\end{document}
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<pre class="moz-signature" cols="72">--
Andrew J. Pounds, Ph.D. (<a class="moz-txt-link-abbreviated" href="mailto:pounds_aj@mercer.edu">pounds_aj@mercer.edu</a>)
Professor of Chemistry and Computer Science
Mercer University, Macon, GA 31207 (478) 301-5627
<a class="moz-txt-link-freetext" href="http://faculty.mercer.edu/pounds_aj">http://faculty.mercer.edu/pounds_aj</a>
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