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On 02/15/2015 06:04 PM, wrote:<br>
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<p>Hi, Dr. Pounds! I was working on the lab and was trying to
figure out the value to use for change in temperature. Do you
just use the initial temperature minus the freezing point you
found on the graph? Thank you!</p>
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So, for the pure solvent (just the paradichlorobenzene) find the
intersection of the two lines like we discussed in class. Look at
the end of the lab procedures if you don't remember what this looks
like. This intersection is the melting point. Then do the same
thing for the solution in which you added the 3 grams of unknown.
Find the melting point of this solution. The difference between
these to melting points is the change in temperature.<br>
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<pre class="moz-signature" cols="72">--
Andrew J. Pounds, Ph.D. (<a class="moz-txt-link-abbreviated" href="mailto:pounds_aj@mercer.edu">pounds_aj@mercer.edu</a>)
Professor of Chemistry and Computer Science
Mercer University, Macon, GA 31207 (478) 301-5627
<a class="moz-txt-link-freetext" href="http://faculty.mercer.edu/pounds_aj">http://faculty.mercer.edu/pounds_aj</a>
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