<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
</head>
<body>
<p>So for the lab that is due tomorrow night you need to turn in a
calibration plot using ONLY THE MERCURY (Hg) LAMP data. I am
attaching a sample plot ( do not try to turn my plot in -- you'll
end up in front of the honor council -- use your own data ).</p>
<p>Here is the link to the <a moz-do-not-send="true"
href="http://theochem.mercer.edu/chm181/atomspec2.png">sample
plot.</a></p>
<p>Once you make your own plot you can use it to determine the
wavelengths of the lines from the other lights and salts. You do
not have to do the candle!</p>
<p>Finally, to calculate the energy for the for the mercury lines
you have to use the equation
<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>E</mi><mo>=</mo><mfrac><mrow><mi>h</mi><mi>c</mi></mrow><mi>λ</mi></mfrac></mrow><annotation
encoding="TeX">E=\frac{h c}{\lambda}</annotation></semantics></math></p>
<p>Where h is Planck's constant in J sec, c is the speed of light in
meters/sec and lambda is the wavelength in meters. Use nanometers
on your graph but in your calculation of energy remember to
convert to meters.</p>
<p>Example: A photon with a wavelength of 418 nm has an energy of</p>
<p>E = (6.626x10^-34)(3x10^8)/(418x10^-9) = 4.756x10^-19 Joules <br>
</p>
<p>4.756x10^-19 x 6.022x10^23 = 286400 Joules / mol = 286.4 kJ/mol<br>
</p>
<div class="moz-signature">-- <br>
<b>Andrew J. Pounds, Ph.D.</b><br>
<i>Professor of Chemistry and Computer Science</i><br>
<i>Director of the Computational Science Program</i><br>
<i>Mercer University, Macon, GA, 31207 (478) 301-5627 </i></div>
</body>
</html>