[CHM 331] Problem 18.34

[Andrew J. Pounds]

On 03/16/2017 06:15 PM, wrote:
>
> I am having trouble with deriving the equation for 3g. I am 
> completely lost on the problem
>
> ------------------------------------------------------------------------

Since we know the 3D eigenvalue expression is going to be something like

$E = (n_x + \frac{1}{2}) h \nu_x + (n_y + \frac{1}{2}) h \nu_y + (n_z + 
\frac{1}{2}) h \nu_z $
**
and since the problem tells you that you are dealing with the isotropic 
case ($k_x=k_y=k_z$), which
means that the $\nu$'s have to equal each other, you could come up with

$E = (n_x + n_y + n_z + \frac{3}{2}) h \nu$


-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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