<html>
<head>
<meta content="text/html; charset=ISO-8859-1"
http-equiv="Content-Type">
</head>
<body bgcolor="#FFFFFF" text="#000000">
<br>
On 09/15/2012 12:09 AM, Christine.O.Conroy wrote:
<blockquote
cite="mid:CA765D0D95A04D449667AFA14377899C5560D746CB@MERCERMAIL.MercerU.local"
type="cite">
<meta http-equiv="Content-Type" content="text/html;
charset=ISO-8859-1">
<style type="text/css" id="owaParaStyle"></style>
<div style="direction: ltr;font-family: Tahoma;color:
#000000;font-size: 10pt;">For 9.26 a,
<div><br>
</div>
<div><br>
</div>
<div>In class we found that </div>
<div>k=4 pi^2 v^2 m</div>
<div><br>
</div>
<div>In the book it says</div>
<div>m(mu)=m1m2/(m1+m2)</div>
<div><br>
</div>
<div>So for 35 Cl2 I found that </div>
<div><br>
</div>
<div>k=4 (pi^2) (5.6)^ 2 m</div>
<div><br>
</div>
<div>for m I found the mass of one Cl atom by dividing .035 by
avogandros number getting 5.812E-26 and then found mu to be
(5.812E-26)^2 / (2*5.812E-26) and got a value of 2.906E-26
kg. </div>
<div><br>
</div>
<div>so k =4 pi^2 (5.6)^2 (2.906E-26)</div>
<div><br>
</div>
<div><br>
</div>
<div>But that is not the answer in the back of the book. </div>
<div><br>
</div>
<div>I looked online and it seems that some equations include c
or the speed of light in the equation (ie k= m(2*pi*v*c)^2 but
I did't see this in the notes or in the book and regardless
adding it does not give me the correct answer. </div>
<div><br>
</div>
<div><br>
</div>
<div>Could you help?</div>
</div>
</blockquote>
<br>
The first problem I see is your conversion to reciprocal meters.
Because it is an inverse relationship you multiply to 100 (to get
56000 ), not divide by 100.<br>
<br>
<br>
<br>
<pre class="moz-signature" cols="72">--
Andrew J. Pounds, Ph.D. (<a class="moz-txt-link-abbreviated" href="mailto:pounds@theochem.mercer.edu">pounds@theochem.mercer.edu</a>)
Associate Professor of Chemistry and Computer Science
Mercer University, Macon, GA 31207 (478) 301-5627
</pre>
</body>
</html>