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<div class="moz-cite-prefix">So if you know one root is positive and
one root it negative you can use the "bounds" option to control
which root is found. Set up the expression as we did in class.
First go for the positive root<br>
<br>
bounds: {0, 100}<br>
initial x: 1<br>
<br>
Then set up for the negative root<br>
<br>
bounds: {-100,0}<br>
initial x: -1<br>
<br>
<br>
On 02/14/2017 01:39 PM, wrote:<br>
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cite="mid:e0627212a3f6443a96421804032486dd@spiderman.MercerU.local"
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<p dir="auto" style="text-align:left; margin-top:25px;
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Dr. Pounds,<br>
I've been reading online but I haven't been able to figure out
the solver in my calculator. I got it to spit out one root but
I can't get past that. Its a ti-84 plus C sliver edition,<br>
Thbaks,</p>
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<pre class="moz-signature" cols="72">--
Andrew J. Pounds, Ph.D. (<a class="moz-txt-link-abbreviated" href="mailto:pounds_aj@mercer.edu">pounds_aj@mercer.edu</a>)
Professor of Chemistry and Computer Science
Mercer University, Macon, GA 31207 (478) 301-5627
<a class="moz-txt-link-freetext" href="http://faculty.mercer.edu/pounds_aj">http://faculty.mercer.edu/pounds_aj</a>
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