[CHM 112] Burdge Problems

[Andrew J. Pounds]

On 07/04/13 22:17,  wrote:
>
> Hey Dr. Pounds,
>
> On Chapter 14 #44, it is asking us to find Temperature 2. I thought I 
> knew how to do it, but I think my algebra is messing up somewhere. On 
> your solutions, you got 644 K, but I keep getting a tiny number. This 
> is my work...
>
> ln(k2/k1)=(Ea/R)[(1/T1)-(1/T2)]
>
> ln(8.80E-4/4.60E-4)= (104000J/8.314 J)[(1/623)-(1/T2)]
>
> .648695418= 12509.02093[(1/623)-(1/T2)]
>
> 5.18582E-5= [(1/623)-(1/T2)]
>
> .0015532782= (1/T2)
>
> THIS IS WHERE I AM GETTING LOST. I am not too sure if I did my math 
> wrong or did the whole problem wrong. Sorry this was so lengthy!
>
> Thank you!
>


You are so close that I a am wondering why you stopped -- you need to 
find $T_2$...

\documentclass{article} \usepackage[utf8x]{inputenc} \pagestyle{empty} 
\begin{document} $\mathrm{0.0015532782} = \frac{1}{T_2}$ %this is where 
your LaTeX expression goes \end{document}

$T_2 = \frac{1}{\mathrm{0.0015532782}}$

$T_2=\mathrm{644}$

That's your temperature in Kelvin -- and the correct answer.

-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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