[CHM 112] Burdge problem

[Andrew J. Pounds]

On 07/06/13 18:25,  wrote:
> In chapter 14 problem 42, why do the constants not divide out to equal 
> one? Because it says "the reaction at 250 degrees celsius is 1.50E3 
> times as fast as the same reaction at 150 degrees celsius."So aren't 
> both the k's 1.50E3?
> ------------------------------------------------------------------------
>

So let's say the rate equation is

RATE = k [CO][Cl_2 ]

The problem tells us that the concentrations are the same for both 
experiments; therefore if the RATE is changing by 1500 times, then it is 
due to the fact that "k" is 1500 times greater at 250 K than it is at 
150 K.

Now think about this, since I am going to be using the ratio of these 
two k's in the equation, I don't have to actually know their values -- 
just their relative sizes.  When I worked the problem I set k_1 =1 and 
k_2 =1500.

Hope that helps.

-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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