[CHM 112] Burdge

[Andrew J. Pounds]

On 07/20/13 10:28, Liza Michael Klyachkin wrote:
> Okay in chapter 16 problem 72, I don't understand why you have to 
> subtract 10.88 from 14? You are suppose to find the Kb but that's a 
> base and 10.88 is the number for a base but 3.12 is for an acid...when 
> you subtract 10.88 form 14.
> On Jul 20, 2013, at 7:01 AM, Andrew J. Pounds wrote:
>

Alright -- here we go.  We want to find the $K_b$ for this weak base 
(let's call it ZH3).

$K_b = \frac{[ZH_4^+][OH^-]}{[ZH_3]}= \frac{(x)(x)}{0.19-x}$

Now, they gave us the pH -- but we need the OH^- concentration to plug 
in for $x$.  In the problem I found the pOH from the pH and then used 
that to find the [OH^- ] using the techniques we discussed in class.

-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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