[CSC 315] Barycentric cordinates

[Andrew J. Pounds]

On 09/29/14 19:08,  wrote:
>
> What exactly is alpha in barycentric coordinates, If that is not 
> needed, how does one figure out the barycentric coordinates without alpha?
>
>
> -Kevin Long
>

It is effectively the "third variable" that one has to have to form the 
three equations in three unknowns.  For example, if you look on page 26 
of the second set of notes, you could rewrite the matrix as a 3x3

1     1      1

0    xb-xc   xc-xa

0   yb-ya   yc-ya

the solution vector be

alpha

beta

gamma


and the right vector be


1

xp-xa

yp-ya






-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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