[CHM 112] Burdge #66

[Andrew J. Pounds]

On 04/21/2015 12:01 PM,  wrote:
> Dr. Pounds,
> For Burdge problem #66, I understand that Fe(OH)3 will be more soluble in acid because it is a base, but could you explain why they other two answers are more soluble.
>
> Thanks,

So when BaSO4 and CaCO3 go into solution they leave conjugate bases of 
weak acids in solutions.  As such, if there is an acid around the H from 
the acid is going to combine with them (HSO_4 ^- and HCO_3 ^- ). By 
removing the ions from the solution, the system responds via 
LeChateliers principle and puts more of the SO4^2- and CO3^2- in 
solution.  As such, these ions are more soluble in acid.

-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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