[CHM 115] Lab

[Andrew J. Pounds]

Look closely at the figure on the first page of the Standardization of 
NaOH lab procedures.  The phthalate has a acidic hydrogen ion that is 
replaced by the sodium.  The hydrogen that is replaced by the sodium 
then combines with the OH to make water.  This happens on a 1:1 basis.

On 09/10/14 10:55, jll2014shs at gmail.com wrote:
> I’m doing the lab that's due tomorrow and I cant figure out the 
> equation. in the back ground it says that KNaP is produced but that 
> means the Carbon from the KHP just disappears. So should I listen to 
> google who says NaOH + C8H5KO4 yields NaC8H4KO4 and water? Or use the 
> back ground and have the Carbon disappear? Or am I totally missing 
> something?
>
> Thanks,
>


-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://theochem.mercer.edu/pipermail/chm115/attachments/20140910/6ab47782/attachment.html>