[CHM 331] 331 hmwk set 1

[Andrew J. Pounds]

The energy of the ejected electron after you exceed the work function of 
the metal is given by

E = h nu - phi

Some older texts expressed this as

-E = phi - h nu

to reiterate the point that the electron would not leave the surface 
(with a negative energy) unless the energy of the work function was 
exceeded by the incident radiation (resulting in a positive energy).  I 
must have resorted to that equation in my head and written just left off 
the initial negative sign.  Sorry about that.


On 08/28/2012 05:00 PM,  wrote:
>
> Dr. Pounds,
>
> On problem 9.3 from Alberty and Silvey,  the book uses 
> E=h*(nu)-(phi).  In class you gave us E=(phi)-h*(nu).  Which of these 
> is correct?
>
> Thanks,
>
>


-- 
Andrew J. Pounds, Ph.D.  (pounds at theochem.mercer.edu)
Associate Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627

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