[CHM 112] Additional Problems

[Andrew J. Pounds]

In the numerator you missed a cubed term.

0=104-((2.00+x)(1.00+3x))/((6.50-x)(8.50-x))

should be

0=104-((2.00+x)(1.00+3x)^3)/((6.50-x)(8.50-x))

On 07/12/13 14:35, wrote:
>
> Hey Dr. Pounds,
>
> I was doing the additional problems for chapter 15 and 18. I was 
> working on number 3 and I used my solver to find x. You got the value 
> 2. 44. I keep getting 5.94. Can you help me figure out what I am doing 
> wrong.
>
> This is what I put into my calculator for the equation.
>
> 0=104-((2.00+x)(1.00+3x))/((6.50-x)(8.50-x))
>
> My x was set to 0 and then my bounds were {0,6,50}
>
> I clicked alpha enter. I still am not getting the correct answer.
>
> Thank you!
>


-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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