[CHM 112] Burdge problem

[Andrew J. Pounds]

On 07/14/13 16:27,  wrote:
> In chapter 18, problem 82 how do you get the answer for O2 from the 
> equation: 6.89E.38= (PO2)^1/2
> On Jul 13, 2013, at 9:48 AM, Andrew J. Pounds wrote:
>
>>

Think about it this way

$3 = x^{\frac{1}{2}}$

$3^2 = (x^{\frac{1}{2}})^2$

$9 = x$

And check you equation... that is 6.89E-38.  If I square it I get 4.75E-75


-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://theochem.mercer.edu/pipermail/chm112/attachments/20130714/c73f751e/attachment.html>
-------------- next part --------------
A non-text attachment was scrubbed...
Name: tblatex-8.png
Type: image/png
Size: 851 bytes
Desc: not available
URL: <http://theochem.mercer.edu/pipermail/chm112/attachments/20130714/c73f751e/attachment.png>
-------------- next part --------------
A non-text attachment was scrubbed...
Name: tblatex-7.png
Type: image/png
Size: 1184 bytes
Desc: not available
URL: <http://theochem.mercer.edu/pipermail/chm112/attachments/20130714/c73f751e/attachment-0001.png>
-------------- next part --------------
A non-text attachment was scrubbed...
Name: tblatex-6.png
Type: image/png
Size: 735 bytes
Desc: not available
URL: <http://theochem.mercer.edu/pipermail/chm112/attachments/20130714/c73f751e/attachment-0002.png>