[CHM 112] Freezing Point Depression Lab

[Andrew J. Pounds]

On 02/15/2015 06:04 PM,  wrote:
>
> ​Hi, Dr. Pounds!  I was working on the lab and was trying to figure 
> out the value to use for change in temperature.  Do you just use the 
> initial temperature minus the freezing point you found on the graph?  
> Thank you!
>
>
>

So, for the pure solvent (just the paradichlorobenzene) find the 
intersection of the two lines like we discussed in class.  Look at the 
end of the lab procedures if you don't remember what this looks like.   
This intersection is the melting point.   Then do the same thing for the 
solution in which you added the 3 grams of unknown. Find the melting 
point of this solution.  The difference between these to melting points 
is the change in temperature.



-- 
Andrew J. Pounds, Ph.D.  (pounds_aj at mercer.edu)
Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627
http://faculty.mercer.edu/pounds_aj

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