[CHM 331] Normalization

[Andrew J. Pounds]

Several of you were asking about the end of the normalization problem I 
did yesterday and how I determined the value for B.  While I'm working 
on rebuilding my "in mail math fonts" here are the basics...

1 = integral{ 0 to L} B^2 sin^2(n pi x / L) dx

we brought the B^2 out front

1 = B^2 integral{ 0 to L} sin^2(n pi x / L) dx

on the board I went through and determined that the value of the
integral was L/2.  This leaves us with

1 = B^2 L/2

move the L/2 to the other side and rearrange

B^2 = 2/L

thus

B = sqrt(2/L)

Does that help?





-- 
Andrew J. Pounds, Ph.D.  (pounds at theochem.mercer.edu)
Associate Professor of Chemistry and Computer Science
Mercer University,  Macon, GA 31207   (478) 301-5627